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whai 2024-03-16 19:02:55 +08:00
parent b633f27b27
commit 99bda3a447
13 changed files with 818 additions and 1 deletions
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67
src/main/java/cn/whaifree/leetCode/BackTracking/LeetCode698.java Normal file
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@ -0,0 +1,67 @@
package cn.whaifree.leetCode.BackTracking;
import org.junit.Test;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/15 14:51
* @注释
*/
public class LeetCode698 {
@Test
public void test() {
int[] nums = {4, 3, 2, 3, 5, 2, 1};
int k = 4;
System.out.println(new Solution().canPartitionKSubsets(nums, k));
}
class Solution {
public int[] numUsed;
public boolean canPartitionKSubsets(int[] nums, int k) {
numUsed = new int[nums.length];
Arrays.sort(nums);
int sum = Arrays.stream(nums).sum();
if (sum % k != 0 || nums[nums.length - 1] > sum / k)
return false;
return divideGroups(nums, nums.length - 1, sum / k, 0, k);
}
/**
*
* @param nums
* @param start
* @param target
* @param current
* @param k
* @return
*/
public boolean divideGroups(int[] nums, int start, int target, int current, int k) {
if (k == 1)
return true; // 分组操作执行k-1次之后，最后剩余的元素，就是最后一组了，不需要再匹配
if (current == target)
return divideGroups(nums, nums.length - 1, target, 0, k - 1); // 分组操作执行k-1次后，最后剩余的元素，就是最后一组了，不需要再匹配
for (int i = start; i >= 0; i--) {
if (numUsed[i] == 1 || current + nums[i] > target) continue; // 被使用的元素，不能再次使用；总和大于目标值，也不能使用
numUsed[i] = 1; // 标记占用
if (divideGroups(nums, i - 1, target, current + nums[i], k)) return true;
numUsed[i] = 0; // 撤销标记
while (i > 0 && nums[i - 1] == nums[i]) i--; // 例如“12333333...”，假如最右侧的“3”这个值没有匹配上，那么它左侧的剩余五个“3”都不需要再匹配了。
}
return false;
}
}
}

123
src/main/java/cn/whaifree/leetCode/Dynamic/BeiBao.java
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@ -12,10 +12,29 @@ public class BeiBao {
@Test
public void main() {
//
// new Thread(() -> {
// try {
// Thread.sleep(1000);
// } catch (InterruptedException e) {
// throw new RuntimeException(e);
// }
// }).start();
//
// new Thread(() -> {
//
// }).start();
//
//
// String a = "a";
//
// String b = new String("a");
//
// System.out.println(a == b);
int[] weight = {1,3,4};
int[] value = {15,20,30};
int bagSize = 4;
new Solution().packageProblem(weight, value, bagSize);
new Solution2().packageProblem(weight, value, bagSize);
}
class Solution{
@ -81,4 +100,106 @@ public class BeiBao {
}
}
class Solution1{
/**
* dp[i][j] i表示商品，j表示空间 dp[i][j]表示 容量为j为包裹，从0-i个商品中取得最大值
*
* 初始化
* 0 1 2 3 4 5 包容量
* 物品0 0 0 2 2 2 2
* 物品1 0
* 物品2 0
*
* dp[i][j] 表示从下标为[0-i]的物品里任意取，放进容量为j的背包，价值总和最大是多少。
*
* @param weights 物品的重量
* @param values 物品的价值
* @param carryNumber 可以携带的数量
* @return
*/
public int packageProblem(int[] weights, int[] values, int carryNumber) {
int length = weights.length;
int[][] dp = new int[length][carryNumber + 1];
for (int i = 0; i < length; i++) {
dp[i][0] = 0;
}
for (int i = weights[0]; i <= carryNumber; i++) {
dp[0][i] = values[0];
}
// 如果i 不放东西 dp[i][j] = dp[i-1][j]
// 如果i 放东西 dp[i][j] = max(dp[i-1][j],dp[i-1][j-weight[i]]-value[i])
// i为商品；j为容量。
for (int i = 1; i < length; i++) {
for (int j = 1; j <= carryNumber; j++) {
if (weights[i] > j) {
// 重量太大，放不进去
dp[i][j] = dp[i - 1][j];
}else {
dp[i][j] = Math.max(dp[i - 1][j], dp[i - 1][j - weights[i]] + values[i]);
}
}
}
return dp[length - 1][carryNumber];
}
}
class Solution2{
/**
*
* dp[i][j] 表示从下标为[0-i]的物品里任意取，放进容量为j的背包，价值总和最大是多少。
* dp[j] 表示容量为j的背包的最大价值总和
*
* 初始化
* 0 1 2 3 4 5 包容量
* 物品0 0 0 2 2 2 2
* 物品1 0
* 物品2 0
*
* 不放这个商品 那价值不变，还是dp[j]
* dp[j] = max(dp[j] , dp[j-weight[i]]+value[i]])
*
* @param weights 物品的重量
* @param values 物品的价值
* @param carryNumber 可以携带的数量
* @return
*/
public int packageProblem(int[] weights, int[] values, int carryNumber) {
int length = weights.length;
int[] dp = new int[carryNumber + 1];
// 不放这个商品 那价值不变，还是dp[j]
// dp[j] = max(dp[j] , dp[j-weight[i]]+value[i]])
// i为商品；j为容量。
for(int i = 0; i < length; i++) { // 遍历物品
for(int j = carryNumber ;j >= weights[i]; j--) { // 遍历背包容量
dp[j] = Math.max(dp[j], dp[j - weights[i]] + values[i]);
}
/**
* 倒序遍历是为了保证物品i只被放入一次！。但如果一旦正序遍历了，那么物品0就会被重复加入多次！
*
* 举一个例子：物品0的重量weight[0] = 1，价值value[0] = 15
* 如果正序遍历
* dp[1] = dp[1 - weight[0]] + value[0] = 15
* dp[2] = dp[2 - weight[0]] + value[0] = 30
*
* 此时dp[2]就已经是30了，意味着物品0，被放入了两次，所以不能正序遍历。
*/
}
return dp[carryNumber];
}
}
}

207
src/main/java/cn/whaifree/leetCode/Dynamic/LeetCode416.java Normal file
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@ -0,0 +1,207 @@
package cn.whaifree.leetCode.Dynamic;
import org.junit.Test;
import java.util.Arrays;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/14 12:24
* @注释
*/
public class LeetCode416 {
@Test
public void test() {
int[] nums = {1,2,3,5};
boolean canPartition = new Solution3().canPartition(nums);
System.out.println(canPartition);
}
// class Solution {
// /**
// * 分割为2部分
// * @param nums
// * @return
// */
// public boolean canPartition(int[] nums) {
// Arrays.sort(nums);
//
// int rightSum = 0;
// for (int num : nums) {
// rightSum += num;
// }
// int leftSum = 0;
// for (int i = 0; i < nums.length; i++) {
// if (leftSum == rightSum) {
// return true;
// } else if (leftSum > rightSum) {
// return false;
// }
// leftSum += nums[i];
// rightSum -= nums[i];
// }
// return false;
// }
// }
class Solution {
int sumHalf = 0;
int nowSum = 0;
/**
* 回溯
*
* @param nums
* @return
*/
public boolean canPartition(int[] nums) {
for (int num : nums) {
sumHalf += num;
}
sumHalf /= 2;
return backTracking(nums, 0);
}
public boolean backTracking(int[] nums, int start) {
if (nowSum == sumHalf) {
return true;
}else if (nowSum>sumHalf){
return false;
}
boolean b = false;
for (int i = start; i < nums.length; i++) {
nowSum += nums[i];
b = backTracking(nums, i + 1);
// 不行，有可能某些元素没在集合内
nowSum -= nums[i];
if (b==true) return true;
}
return b;
}
}
class Solution2 {
/**
* 转换为背包问题
* nums 为商品的重量、同时为商品的价值
* 背包容量为sum/2 且需要装满
*
* 0 1 2 3 4 5
* 0 0 n0 n0 n0 n0 n0
* 1 0
* 2 0
* 3 0
* 4 0
* 5 0
*
* 不放东西的最大价值 dp[i][j] = dp[i-1][j]
* 放东西的最大价值 max(dp[i-1][j] , dp[i-1][j-nums[i]]+values[i])
*
* @param nums
* @return
*/
public boolean canPartition(int[] nums) {
int sumHalf = 0;
for (int num : nums) {
sumHalf += num;
}
if (sumHalf % 2 != 0) {
return false;
}
sumHalf /= 2;
int length = nums.length;
int[][] dp = new int[length][sumHalf + 1];
// for (int i = 0; i < length; i++) {
// dp[i][0] = 0;
// }
for (int i = nums[0]; i <= sumHalf; i++) {
dp[0][i] = nums[0];
}
for (int i = 1; i < length; i++) {
for (int j = 1; j <= sumHalf; j++) {
if (nums[i] > j) {
// 放不下
dp[i][j] = dp[i - 1][j];
} else {
dp[i][j] = Math.max(dp[i - 1][j], dp[i - 1][j - nums[i]] + nums[i]);
}
if (dp[i][j] == sumHalf) {
return true;
}
}
}
return false;
}
}
class Solution3 {
/**
* 将nums的元素放入背包中
* 1. 背包容量 sum/2
* 2. 物品i重量nums[i]；价值nums[i]
*
* 0 1 2 3 4 5
* 0
* 1
* 2
*
* dp[j]表示 j背包容量的最大价值
*
*
*
* // 递推公式
* 2. 放下 dp[j] = max（dp[j], dp[j-weight[i]]+nums[i]）
*
* 从后往前循环，每次取得状态不会和之前取得状态重合，这样每种物品就只取一次了。
*
* @param nums
* @return
*/
public boolean canPartition(int[] nums) {
int sum = 0;
for (int num : nums) {
sum += num;
}
if (sum % 2 != 0) {
return false;
}
// 包裹最大容量
int packageCapacity = sum / 2;
int[] dp = new int[packageCapacity + 1];
for (int i = 0; i < nums.length; i++) {
// 包的容量必须大于物品i重量才能放进去
/**
* 如果正序遍历
* dp[1] = dp[1 - weight[0]] + value[0] = 15
* 此时容量1的背包已经放入了
* dp[2] = dp[2 - weight[0]] + value[0] = 30
* 此时又放入了一次
*/
for (int j = packageCapacity; j >= nums[i]; j--) {
dp[j] = Math.max(dp[j], dp[j - nums[i]] + nums[i]);
//剪枝一下，每一次完成內層的for-loop，立即檢查是否dp[target] == target，優化時間複雜度（26ms -> 20ms）
if(dp[packageCapacity] == packageCapacity)
return true;
}
}
// 包裹容量和目标值一样
return dp[packageCapacity] == packageCapacity;
}
}
}

44
src/main/java/cn/whaifree/leetCode/Tes1.java
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@ -166,4 +166,48 @@ public class Tes1 {
t2.start();
}
}
class Sun implements Inter,Outer {
public static void main(String[] args) {
new Sun().testDefault();
Inter.testStatic();
}
/**
* 必须重写
*/
@Override
public void testDefault() {
Outer.super.testDefault();
Inter.super.testDefault();
}
}
interface Inter{
default void testDefault(){
System.out.println("testDefault");
}
static void testStatic(){
System.out.println("testStatic");
}
}
interface Outer{
default void testDefault(){
System.out.println("testDefault outer");
}
static void testStatic(){
System.out.println("testStatic outer");
}
}

42
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode343.java Normal file
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@ -0,0 +1,42 @@
package cn.whaifree.redo.redo_24_3_16;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 16:59
* @注释
*/
public class LeetCode343 {
class Solution {
/**
* dp[j] 表示拆分出j后的乘积最大值
*
* dp[j]=
* (j-i)*j 两个数相乘 或
* dp[j-i] * i
*
* dp[j] = dp[j-1] *
* @param n
* @return
*/
public int integerBreak(int n) {
int[] dp = new int[n + 1];
dp[0] = 1;
dp[1] = 1;
dp[2] = 1;
for (int i = 3; i <= n; i++) {
for (int j = 1; j < i - 1; j++) {
dp[i] = Math.max(
dp[i],
Math.max((i - j) * j, dp[i - j] * j)
);
}
}
return dp[n];
}
}
}

59
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode435.java Normal file
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@ -0,0 +1,59 @@
package cn.whaifree.redo.redo_24_3_16;
import org.junit.Test;
import java.util.Arrays;
import java.util.Comparator;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 17:42
* @注释
*/
public class LeetCode435 {
@Test
public void test() {
// int[][] intervals = {{1,2},{2,3},{3,4},{1,3}};
// int result = new Solution().eraseOverlapIntervals(intervals);
// System.out.println(result);
//
//
// // [ [1,2], [1,2], [1,2] ]
// int[][] intervals1 = {{1,2},{1,2},{1,2}};
// int result1 = new Solution().eraseOverlapIntervals(intervals1);
// System.out.println(result1);
// [[1,100],[11,22],[1,11],[2,12]]
int[][] intervals2 = {{1,100},{11,22},{1,11},{2,12}};
int result2 = new Solution().eraseOverlapIntervals(intervals2);
System.out.println(result2);
}
class Solution {
public int eraseOverlapIntervals(int[][] intervals) {
// 最多能参加几次活动
Arrays.sort(intervals, new Comparator<int[]>() {
@Override
public int compare(int[] o1, int[] o2) {
return o1[0] - o2[0];
}
});
int participation = 1;
for (int i = 1; i < intervals.length; i++) {
if (intervals[i][0] < intervals[i - 1][1]) {
// 后一个活动的开始时间早于头一个活动开始时间，这个活动不能参加
intervals[i][1] = Math.min(intervals[i - 1][1], intervals[i][1]);
}else {
participation++;
}
}
return intervals.length - participation;
}
}
}

45
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode45.java Normal file
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@ -0,0 +1,45 @@
package cn.whaifree.redo.redo_24_3_16;
import org.junit.Test;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 18:27
* @注释
*/
public class LeetCode45 {
@Test
public void test() {
int[] nums = new int[]{2, 3, 1, 1, 4};
int jump = new Solution().jump(nums);
System.out.println(jump);
}
class Solution {
public int jump(int[] nums) {
if (nums.length == 1) {
return 0;
}
int jump = 0;
int maxCover = 0;
int curCover = 0; // 用于标记是否达到一次跳的终点
for (int i = 0; i < nums.length; i++) {
maxCover = Math.max(maxCover, nums[i] + i);
if (i == curCover) {
jump++;
curCover = maxCover;
}
if (curCover >= nums.length - 1) {
return jump;
}
}
return jump;
}
}
}

46
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode738.java Normal file
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@ -0,0 +1,46 @@
package cn.whaifree.redo.redo_24_3_16;
import org.junit.Test;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 18:04
* @注释
*/
public class LeetCode738 {
@Test
public void test() {
Solution solution = new Solution();
int n = 668799 ;
int n1 = 668799;
System.out.println(solution.monotoneIncreasingDigits(n));
}
class Solution {
public int monotoneIncreasingDigits(int n) {
// 668841 668799
// 遍历的过程-1 ，再找到最后一个递减的然后 后面全部替换为9
char[] chars = String.valueOf(n).toCharArray();
int index = Integer.MAX_VALUE;
for (int i = chars.length - 1; i > 0; i--) {
if (chars[i] < chars[i - 1]) {
chars[i-1]--;
index = i;
}
}
for (int i = index; i < chars.length ; i++) {
chars[i] = '9';
}
return Integer.parseInt(new String(chars));
}
}
}

51
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode763.java Normal file
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@ -0,0 +1,51 @@
package cn.whaifree.redo.redo_24_3_16;
import org.junit.Test;
import java.util.ArrayList;
import java.util.List;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 17:53
* @注释
*/
public class LeetCode763 {
@Test
public void test() {
String s = "ababcbacadefegdehijhklij";
Solution solution = new Solution();
List<Integer> list = solution.partitionLabels(s);
System.out.println(list);
}
class Solution {
public List<Integer> partitionLabels(String s) {
// 统计每个字符最后出现的位置
int[] map = new int[26];
char[] chars = s.toCharArray();
for (int i = 0; i < chars.length; i++) {
map[chars[i] - 'a'] = i;
}
List<Integer> list = new ArrayList<>();
int left = 0;
int rightMax = 0;
for (int i = 0; i < chars.length; i++) {
rightMax = Math.max(map[chars[i] - 'a'], rightMax);
if (i == map[chars[i] - 'a'] && rightMax == i) {
list.add(rightMax - left + 1);
left = rightMax + 1;
}
}
return list;
}
}
}

41
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode96.java Normal file
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@ -0,0 +1,41 @@
package cn.whaifree.redo.redo_24_3_16;
import org.junit.Test;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 16:40
* @注释
*/
public class LeetCode96 {
@Test
public void test() {
int n = 4;
int result = new Solution().numTrees(n);
System.out.println(result);
}
class Solution {
public int numTrees(int n) {
if (n == 1) {
return 1;
}
//dp[i]表示i个节点的可能的树的数量
int[] dp = new int[n + 1];
dp[0] = 1;
dp[1] = 1;
dp[2] = 2;
for (int i = 3; i <= n; i++) {
for (int j = 1; j <= i; j++) {
dp[i] += dp[i - j] * dp[j - 1];
}
}
return dp[n];
}
}
}

64
src/main/java/cn/whaifree/redo/redo_24_3_16/LeetCode968.java Normal file
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@ -0,0 +1,64 @@
package cn.whaifree.redo.redo_24_3_16;
import cn.whaifree.leetCode.model.TreeNode;
import org.junit.Test;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/16 18:18
* @注释
*/
public class LeetCode968 {
@Test
public void test() {
TreeNode treeNode = TreeNode.constructTreeByArray(0,0,null,0,0);
System.out.println(new Solution().minCameraCover(treeNode));
}
class Solution {
int res = 0;
/**
* 0 被覆盖
* 1 有监控
* 2 没覆盖
*
* @param root
* @return
*/
public int minCameraCover(TreeNode root) {
if (circle(root) == 2) {
res++;
}
return res;
}
public int circle(TreeNode root) {
if (root == null) {
return 0;
}
int left = circle(root.left);
int right = circle(root.right);
// 左边或者右边有未覆盖的，就在这里安排一个监控
if (left == 2 || right == 2) {
res++;
return 1;
}
// 左边和右边有监控，这里就被覆盖了
if (left == 1 || right == 1) {
return 0;
}
// 左右都覆盖，这里就没覆盖
if (left == 0 && right == 0) {
return 2;
}
return -1;
}
}
}

13
src/main/java/cn/whaifree/test/Custom.java Normal file
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@ -0,0 +1,13 @@
package cn.whaifree.test;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/14 14:58
* @注释
*/
@FunctionalInterface
public interface Custom {
void f();
}

17
src/main/java/cn/whaifree/test/LambdaClass.java Normal file
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@ -0,0 +1,17 @@
package cn.whaifree.test;
/**
* @version 1.0
* @Author whai文海
* @Date 2024/3/14 14:58
* @注释
*/
public class LambdaClass {
public static void main(String[] args) {
new LambdaClass().lambdaInterfaceDemo(()-> System.out.println("自定义函数式接口"));
}
//函数式接口参数
void lambdaInterfaceDemo(Custom i){
i.f();
}
}